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For scattering by an .inverse square. field (such as that produced by a charged nucleus in Rutherford.s model), the relation between impact parameter b and the scattering angle theta is given by, b=(Ze^(2)cot theta//2)/(4pi epsilon_(0)((1)/(2)mv^(2))) For a given imapct parameter b, does the angle of deflection increase or decrease with increase in energy ? |
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Answer» SOLUTION :Given relation: `b=(Ze^(2)cot theta//2)/(4pi epsilon_(0)((1)/(2)mv^(2)))` For given b, `(Ze^(2)cot theta//2)/(4pi epsilon_(0)((1)/(2)mv^(2)))`= constant As the energy `(mv^(2)//2)` increases, the value of `cot theta//2` increases. THEREFORE, the value of scattering ANGLE `theta` decreases as expected. |
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