1.

For second order reaction

Answer»

`K=(2.303)/(t)LOG.(B(a-x))/(a(b-x))`
`K=(2.303)/(t(a-b))log.(b(a-x))/(a(b-x))`
`K=(2.303)/(t(a-b))log.(a(a-x))/(b(b-x))`
`K=(2.303)/(t(b-a))log.(a(a-x))/(b(b-x))`

ANSWER :B


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