1.

For steel the breaking stress is 6 xx 10^6 N /m^2 and the density is 8xx10^3kg/m^3 What is the maximum length of a steel wire , which can be suspended without breaking under its own weight?

Answer»

Solution :WEIGHT = MG = V d g = A L d g
Breaking stress = `(Mg)/A = (ALdg)/A`
Ldg[L maximum length]
`therefore L = "Breaking stress"/(dg) = (8 XX 10^6)/(8 xx 10^3 xx 10) = 100m`


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