1.

For the cell given below Zn|Zn^(2+)||Cu^(2+) | Cu, (E_("cell")-E_("cell")^(0))is -0.12 V . It will be when :

Answer»

`[ZN^(2+)]//[CU^(2+)]=10^(2)`
`[Zn^(2+)]//[Cu^(2+)]=10^(-2)`
`[Zn^(2+)]//[Cu^(2+)]=10^(4)`
`[Zn^(2+)]//[Cu^(2+)]=10^(-4)`

Solution :`E = E^(0)-(0.0591)/(2) log""([Zn^(+2)])/([Cu^(+2)]) , (E_("cell") - E_("cell")^(0)) =(-0.86)/(2) log""([Zn^(+2)])/([Cu^(+2)])-0.12 = (-0.06)/(2) log""([Zn^(+2)])/([Cu^(+2)])`
`log""([Zn^(+2)])/([Cu^(+2)]) = (0.12 XX 2)/(0.06) = (0.24)/(0.06) = 4, ([Zn^(+2)])/([Cu^(+2)]) = 10^(4)`


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