1.

For the cell , Hg,Hg_2 Cl_2//Cl (0.1M)//Cl^(-)(0.01M)//Cl_2, Pt E_("cell")^@ is 1.10V , Hence , E_("cell")is

Answer»

1.1591V
`-1.1591V`
1.0409 V
`-1.0409 V`

ANSWER :A


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