1.

For the cell prepared from electrode A and B , Electrode A : Cr_(2)O_(7)^(2-) | Cr^(3+) , E_("red")^(@) = 1.33 V and Electrode B : Fe^(3+) | Fe^(2+) , E_("red")^(@) = 0.77V . Which of the following statement is correct ?

Answer»

The electrons will flow from B to A when connection are MADE
The emf of the cell will be `-0.56`V
A will be negative electrode
B will be positive electrode

Solution :`E_(RP_(Cr_(2)O_(7)^(2-)|CR^(3+))^(@) = 1.33 V ` and `E_(RP_(Fe^(3+)|Fe^(2+))^(@) = 0.77 V E_(RP_(Fe^(3+) |Fe^(2+))^(@) ` is less thus will oxidise or electron will flow Fe(B) electrode to Cr(A) electrode . Also Fe electrons will be negative . Also
`E_(cell)^(@)= E_(RP_(Cr))^(@) - E_(RP_(Fe))^(@)`
`= 1.33 - 0.77 = + 0.56` V


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