1.

For the cell reaction Cu^(2+)(C_(1aq))+Zn_((s))+Zn^(2+)(C_(2aq))+Cu_((s)) of an electrochemical cell, the change in free energy at a given temperature is a function of

Answer»

ln `(C_(1))`
ln `(C_(2))`
ln `(C_(1)+C_(2))`
ln `(C_(2)//C_(1))`

Solution :`E_(cell)=E_(cell)^(@)-(RT)/(nF)` In `(C_(2))/(C_(1)) and DELTAG=-nFE_(cell)`
HENCE `DeltaG` is the FUNCTION of `ln ((C_(2))/(C_(1)))`


Discussion

No Comment Found