1.

For the cell, TI|TI^(+)(0.001M)|Cu^(2+)(0.1M)|Cu,E_(cell) at 25^(@)C is 0.83 V. this can be increased

Answer»

by increasing `[CU^(2+)]`
by increasing `[TI^(+)]`
by decreasing `[Cu^(2+)]`
by decreasing `[TI^(+)]`

Solution :`2TI+Cu^(2+)to2TI^(+)+Cu,E_(cell)-E_(cell)^(@)-(0.0591)/(2)"log"([TI^(+)]^(2))/([Cu^(2+)])`


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