1.

For the cell Zn |Zn^(2+) | | Cu^(2+) | Cu , if the concentration of Zn^(2+) and Cu^(2+) ions is doubled , the emf of the cell

Answer»

DOUBLES
reduces to HALF
remains same
becomes zero

Solution :`E_("cell") = E_("cell")^(@) + (0.059)/(2) "log" ([Cu^(2+)])/([Zn^(2+)])` , THUS on doubling concentration of both `Cu^(2+) and Zn^(2+)` , there will be no effect on `E_("cell")`.


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