1.

For the cellZn(s) | Zn^(2+) || Cu^(2+) | Cu(s) , the standard cell voltageE_("cell")^(0) is 1.10 V . When a cell using these reagents was prepared in the lab, the measured cell voltage was 0.97 V . One possible explanaiton of the observed voltage is

Answer»

there are 2.00 mol of `Cu^(2+) ` bu only 1.00 mol of `ZN^(2+) `
the Zn ELECTRODE had twicethe surfaceof the Cu electrode
the `[Zn^(2+)]` was LARGER than the `[Cu^(2+)]`
the VOLUME of the `Zn^(2+)` SOLUTION was larger than the volume of the `Cu^(2+)` solution

Solution :`Zn + Cu^(+2) to Cu + Zn^(+2) , E=E^(0) + (0.0591)/(2) log""((Cu^(+2))/(Zn^(+2)))`
`0.98 = 1.1 + (0.0591)/(2) log""([Cu^(+2)])/([Zn^(+2)]) ,` So , ` [Zn^(+2)] gt [Cu^(+2)]^(2)`


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