For the circuit in the figure, the voltage and current expressions are:v(t)=E1sin(ωt)+E3sin(3ωt)and i(t)=I1sin(ωt−ϕ1)+I3sin(3ωt−ϕ3)+I5sin(5ωt)The average power measured by the Wattmeter is

For the circuit in the figure, the voltage and current expressions are

1.	For the circuit in the figure, the voltage and current expressions are:v(t)=E1sin(ωt)+E3sin(3ωt)and i(t)=I1sin(ωt−ϕ1)+I3sin(3ωt−ϕ3)+I5sin(5ωt)The average power measured by the Wattmeter is
Answer» For the circuit in the figure, the voltage and current expressions are: $v (t) = E_{1} s i n (ω t) + E_{3} s i n (3 ω t)$ and $i (t) = I_{1} s i n (ω t - ϕ_{1}) + I_{3} s i n (3 ω t - ϕ_{3}) + I_{5} s i n (5 ω t)$ The average power measured by the Wattmeter is

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For the circuit in the figure, the voltage and current expressions are:v(t)=E1sin(ωt)+E3sin(3ωt)and i(t)=I1sin(ωt−ϕ1)+I3sin(3ωt−ϕ3)+I5sin(5ωt)The average power measured by the Wattmeter is

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