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For the circuit shown in the figure, calculate the equivalent resistance for the two cases given as : (1) V_(A) gt V_(B) and (2) V_(B) gt V_(A). Here consider D_(1) and D_(2) to be ideal diodes. |
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Answer» SOLUTION :(1) When `V_(A)gt V_(B)` then `D_(1)` is in forward bias and `D_(2)` is in reverse bias CONNECTION. But second diode is iedeal therefore RESISTANCE `R_(2)` of `D_(2)` is infinite. Therefore CURRENT is flowing throgh only `D_(1)`, so effective resistance is `R_(1)`. In this situation total resistance of the circuit, `R_(AB)=50+0` `therefore R_(AB)=50OMEGA` (2) When `V_(B) gt V_(B)` then, `D_(1)` is in reverse bias and `D_(2)` is in forward bias. Therefore resistance `R_(1)` of `D_(1)` is infinite, so current flowing through `D_(1)` is zero. But effective resistance is only `R_(2)`. `R._(AB)=50+0` `therefore R._(AB)=50Omega` |
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