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For the circuit shown in the figure, the current through the inductor is `0.9A` while the current through the condenser is `0.4 A.` hence the current drawn from the generator is A. `I=1.13` ampB. `I=0.9` ampC. `I=0.5` ampD. `I=0.6` amp |
Answer» Correct Answer - C The current drawn by inductance and capacitor will be in opposite phase. Hence, net current drawn by the generator `=I_(L)-I_(C)=0.9-0.4=0.5` amp |
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