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For the coagulation of 100 ml of arsenious sulphide sol, 5 ml of 1 M NaCl is required. What is the flocculation value of NaCl? |
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Answer» Solution :5 ml of 1 M NaCl contains NaCl ` = 1/1000 xx 5 ` moles = 5 MILLIMOLES Thus, 100 ml of `As_2S_3`SOL require NaCl for COMPLETE coagulation = 5 millimoles . `THEREFORE`1L, i.e., 1000 ml of the sol require NaCl for complete coagulation = 50 millimoles `therefore `By definition, FLOCCULATION value of NaCl = 50. |
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