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For the coagulation of 100 ml of arsenous sulphide sol 4 ml of 1 M NaCl is required . What would be the flocculation value of NaCl? |
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Answer» Solution :4 ml of 1 M NACL contains =`1/1000 times 4=4` milli moles Thus 100 ml of `As_2S_3` SOL REQUIRES NaCl for complete coagulation = 4 milli moles `therefore`1 L i.e. 1000 ml of the sol requires NaCl for complete coagulation = 40 milli moles `therefore` Flocculation value = 40. |
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