1.

For the concentration cell Pt(H_(2))|(HA(0.1M)),(NaA(1M))||(Ha(1M)),(NaA(1M))|(H_(2))Pt""(pK_(a)" of "HA=4) Calculate the cell potential.

Answer»

Solution :Hydrogen electrodes have been SET up in TWO acidic BUFFER solution.
For the buffer, `Ha(0.1M),NaA(1M)`,
`[H^(+)]=K_(a)([HA])/([A^(-)])=10^(-4)xx(0.1)/(1)=10^(-5)M`
for the buffer, `HA(1M),NaA(1M)`,
`[H^(+)]=10^(-4)xx(1)/(1)=10^(-4)M`
for concentration cell, `E_(cell)=(0.0591)/(n)"log"(c_(2))/(c_(1))=(0.0591)/(n)"log"(10^(-4))/(10^(-5))=0.0591Vcong=0.06V`


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