1.

For the decay: ""_(228)Ac overset(-beta)rarr ""^(228)Th overset(-alpha)rarr ""^(224)Ra where lamda (Ac)= 3.14 xx 10^(-5) s^(-1) and lamda(Th)= 1.148 xx 10^(-8) s^(-1). Determine the time for the radioactive daughter to reach its maximum activity

Answer»

Solution :We have, `t= (2.303 (LOG lamda_(1)-log lamda_(2)))/(lamda_(1)-lamda_(2))= (2.303 (log 3.14 XX 10^(-5) - log 1.148 xx 10^(-8)))/(3.14 xx 10^(-5)-1.148 xx 10^(-8))` = `2.52 xx 10^(5)s`


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