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For the decomposition of a compound AB at 600 K the following data were obtained : The order for the decomposition of AB is |
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Answer» 0 `2.75xx10^(-8) = k (0.2)^(n)` `11xx10^(-8) = k(0.40)^(n)` `24.75xx10^(-8) = k (0.6)^(n)` Dividing (II ) by (i) `(11xx10^(-8) )/(2.75xx10^(-8)) = ((0.4)^(n))/((0.2)^(n))` 4= `2^(n)` n=2 |
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