1.

For the decomposition of azoisopropane to hexane and nitrogen at 543 K, the following data is obtained. Calculate the rate constant.

Answer»

Solution :The decomposition reaction is of gaseous nature and expression of the rate equation for the reaction is:
`k =2.303/t log (p_(i))/(2p_(i)-p_(t))`
Rate CONSTANT after 360 s i.e. `k_(360) = 2.303/(360 s) log(35 atm)/(70-54)atm = 2.303/(360S) log 35/16 = 2.303/(360 s) (log 2.1875)`
`=(2.303 xx 0.33995)/(360 s) = 2.17 xx 10^(-3) s^(-1)`
Rate constant after 720 s i.e. `k_(720) = (2.303)/(720 s) log (35 atm)/(70-63) atm`
`=(2.303)/(720 s) log 5 = (2.303 xx 6900)/(720s) log 5 = 2.24 xx 10^(-3)s^(-1)`


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