1.

For the decomposition of H_2O_2(aq) it was found that V_(O_2) (t=15 min) was 100 mL (at 0^@C and 1 atm) while V_(O_2) (maximum) was 200 mL (at 0^@C and 2 atm). If the same reaction had been followed by the titration method of if V_(KMnO_(4))^((cM))(t=0) had been 40 mL, what would V_(KMnO_(4))^((cM))(t=15 min) have been ?

Answer»

30 ML
25 mL
20 mL
15 mL

Solution :`1/4th` reaction has completed UPTO 15 min.Hence `V_(KMnO_4)` will be `3/4xx40=30` mL


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