1.

for the dissociation reaction , H_(2)(g)Leftrightarrow2H(g),DeltaH= 162 kcal heat of atomisation of H is

Answer»

81 KCAL
162 kcal
208 kcal
218 kcal

Solution :`DeltaH=DeltaH_("PRODUCT")DeltaH_(("REACTANT"))`
` 162 =2 xx DeltaH_(H)-DeltaH_(H_(2))`
`DeltaH_(H)=162/2=81 kcal`
`(DeltaH_(H_(H_2))=0)`


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