1.

for the dissociation reaction , `H_(2)(g)Leftrightarrow2H(g),DeltaH= 162 kcal` heat of atomisation of H isA. 81 kcalB. 162 kcalC. 208 kcalD. 218 kcal

Answer» Correct Answer - a
`DeltaH=DeltaH_("product")DeltaH_(("reactant"))`
` 162 =2 xx DeltaH_(H)-DeltaH_(H_(2))`
`DeltaH_(H)=162/2=81 kcal`
`(DeltaH_(H_(H_2))=0)`


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