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for the dissociation reaction , `H_(2)(g)Leftrightarrow2H(g),DeltaH= 162 kcal` heat of atomisation of H isA. 81 kcalB. 162 kcalC. 208 kcalD. 218 kcal |
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Answer» Correct Answer - a `DeltaH=DeltaH_("product")DeltaH_(("reactant"))` ` 162 =2 xx DeltaH_(H)-DeltaH_(H_(2))` `DeltaH_(H)=162/2=81 kcal` `(DeltaH_(H_(H_2))=0)` |
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