1.

For the electrochemical cell, M|M^(+)||X^(-)|X,E^(@)(M^(+)//M)=0.44V and E^(@)(X//X^(-))=0.33V. From this data one can deduce that

Answer»

`M+XtoM^(+)+X^(-)` is the spontaneous reaction
`M^(+)+X^(-)TOM+X` is the spontaneous reaction
`E_(cell)=0.77V`
`E_(cell)=-0.77V`

Solution :For the given cell `M|M^(+)||X^(-)|X`, the cell reaction is derived as follows:
R.H.S. reduction `X+e^(-)TOX^(-)` . . (i)
L.H.S. oxidation `MtoM^(+)+e^(-)`. . . . (ii)
Add (i) and (ii) M+X`toM^(+)+X^(-)`
the cell POTENTIAL `=-0.11V`
Since, `E_(cell)=-ve`, the cell reaction derived above is not spontaneous. In fact, the reverse reaction will occur SPONTANEOUSLY.


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