1.

For the equation 1 - 2 x - x^(2) = tan^(2) (x + y) + cot ^(2) (x + y)

Answer»

exactly one value of X exists
exactly two values of x exists
`y = - 1 + n pi + pi //4, n in Z`
`y = 1 + n pi + pi//4, n in Z`

ANSWER :A


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