1.

For the equilibrium, 2H_(2)(g)+O_(2)(g)hArr2H_(2)O(l) at 25^(@)C,DeltaG^(@) is -474.78kJ mol^(-1). Calculate log K for it (R=8.314 JK^(-1)mol^(-1))

Answer»


SOLUTION :`-DELTAG^(@)=2.303RT" LOG K",""474780=2.303xx8.314xx298" log K or log K"=83.2`


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