1.

For the equilibrium, H_2O(l) iff H_2O_((v)) , which of the following is correct?

Answer»

`Delta G = 0, Delta lt 0 , Delta S lt 0`
`Delta G lt 0 , Delta H gt 0 , Delta S gt 0`
`Delta S gt 0, Delta H = 0 , Delta S gt 0 `
`Delta G = 0, Delta H gt 0, Delta S gt 0`

Solution :`H_2O(l) iff H_2O (v)`
As the process is in EQUILIBRIUM, `Delta G = 0`
` Delta H gt 0`(as the process is ENDOTHERMIC)
` Delta S gt 0`(as entropy increases from LIQUID to gas)


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