1.

For the equilibrium system :2HCl(g)hArr H_(2)(g)+Cl_(2)(g)the equilibrium constant is 1.0xx10^(-5).What is the concentration of HCl if the equilibrium concentration of H_(2) and Cl_(2) are 1.2xx10^(-3) M and 1.2xx10^(-4) M respectively ?

Answer»

`12XX10^(-4)M`
`12xx10^(-3)M`
`12xx10^(-2)M`
`12xx10^(-1)M`

Solution :`K=([H_(2)][Cl_(2)])/([HCL]^(2))`
`1.0xx10^(-5)=((1.2xx10^(-3))(1.2xx10^(-4)))/([HCl]^(2))`
or `[HCl]^(2)=((1.2xx10^(-3))(1.2xx10^(-4)))/(1.0xx10^(-5))`
`=1.44xx10^(-2)`
`[HCl]=sqrt(1.44xx10^(-2))=12xx10^(-2)`


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