InterviewSolution
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InterviewSolution
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For the equilibrium system `2HX(g) hArr H_(2)(g)+X_(2)(g)` the equilibrium constant is `1.0xx10^(-5)`. What is the concentration of HX if the equilibrium concentration of `H_(2)` and `X_(2)` are `1.2xx10^(-3)` M, and `1.2xx10^(-4)` M respectively?A. `12xx10^(-4) M`B. `12xx10^(-3) M`C. `12xx10^(-2) M`D. `12xx10^(-1) M` |
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Answer» Correct Answer - C `{:(,2HX,hArr,H_(2)(g),+,X_(2)(g)),("At equilibrium",?,,1.2xx10^(-3) M,,1.2xx10^(-4) M):}` `K=([H_(2)][X_(2)])/([HX]^(2))` `10^(-5)=(1.2xx10^(-3)xx1.2xx10^(-4))/([HX]^(2))` `[HX]=sqrt((1.2xx1.2xx10^(-7))/(10^(-5)))` `=1.2xx10^(-1)` `=12xx10^(-2) M` |
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