1.

For the equilibriumH_(2)O(l)subH_(2)O(g) at 1 atm and 298 K

Answer»

STANDARD free energy change is equal to zero `(DeltaG^(@)=0)`
Free energy change is less than zero `(DeltaG lt 0)`
Standard free energy change is less than zero `(DeltaG^(@)lt0)`
Standard free energy change is GREATER than zero `(DeltaG^(@)gt0)`

Solution :For reaction `H_(2)O(l)rarrH_(2)O(G)`
`Deltan=1` MEANS POSITIVE.


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