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For the first order reaction 2 N_(2)O_(5)(g) to 4 NO_(2) (g) + O_(2)(g) |
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Answer» The concentration of the reaction DECREASES exponentially with time `t_(1//2) prop (1)/(K) , "" K UARR` on increasing T . After eight half-lives , `C = (C_(0))/(2^(8))` `implies` % completion = `(C_(0) - (C_(0))/(2^(8)))/(C_(0)) xx 100 = 99.6%`. |
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