1.

For the first order reaction 2 N_(2)O_(5)(g) to 4 NO_(2) (g) + O_(2)(g)

Answer»

The concentration of the reaction DECREASES exponentially with time
The half-life of the reaction decreases with increasing TEMPERATURE
The half-life of the reaction depends on the initial concentration of the reactant
The reaction proceeds to 99.6 % completion in eight half-life duration

Solution :`C_(t) = C_(0) e^(-kt)`
`t_(1//2) prop (1)/(K) , "" K UARR` on increasing T .
After eight half-lives , `C = (C_(0))/(2^(8))`
`implies` % completion = `(C_(0) - (C_(0))/(2^(8)))/(C_(0)) xx 100 = 99.6%`.


Discussion

No Comment Found