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For the first order reaction 2" N"_(2)"O"_(5)(g)to4" NO"_(2)(g)+O_(2)(g) |
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Answer» the concentration of the reactant decreases EXPONENTIALLY with time `t_(1//2)=(0.693)/k` As k increases with increasingtempeature, therefore, `t_(1//2)` of a FIRST order reactionis INDEPENDENT of initial concentration. Amount left after 8 half - LIVES `=([A]_0)/(2^8)` `1/(256)"of"[A]_0=0.004"of"'[A]_0` `:." Amount reacted"=0.996" of "[A]_0," i.e," 99.6%" of"[A]_0`. Hence, (d) is correct. |
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