1.

For the first order reaction, calculate the ratio of the time taken to complete 99% of the reaction to the time taken to complete 90% of the reaction.

Answer»


Solution :`t=(2.303)/k LOG a/(a-x)`
`t_(99%) = (2.303)/k log (100)/1=2.303/k XX 2 = 4.606/k`
`t_(90%) = (2.303)/k log 100/10 = 2.303/k xx 1=2.303/k`
`t_(99%)/t_(90%)=4.606/2.303 = 2`.


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