1.

For the following cell Zn(s)|ZnSO_(4)(aq)||CuSO_(4)(aq)|Cu(s) when the concentration of Zn^(2+) is 10 times the concentration of Cu^(2+), the expression for DeltaG (in 1 mol^(-1)) is [F is faraday constant, R is gas constant, T is temperature, E^(@)(cell)=1.1V]

Answer»

`2.303RT+1.1F`
`1.1F`
`2.303RT-2.2F`
`-2.2F`

Solution :Cell REACTION is
`ZN+Cu^(2+)toZn^(2+)+Cu`
`DELTAG=DeltaG^(@)+2.303RTlogQ`
`=DeltaG^(@)+2.303RTlog([Zn^(2+)])/([Cu^(2+)])`
`DeltaG^(@)=-nFE_(cell)^(@)=-2F(1.1)`
`thereforeDeltaG=-2F(1.1)+2.303RTlog10`
`=2.303RT-2.2F`


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