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For the following equilibrium, `2SO_(2)(g) +O_(2)(g) hArr 2SO_(3)(g)` the total equilibrium pressure is `P_(1)`. If volume of the system is reduced to `1//2` of this initial volume then equilibrium is restablished. The new equilibrium total pressure will be `:`A. `2P_(1)`B. `3P_(1)`C. `3.5P_(1)`D. less than `2P_(1)` |
Answer» Correct Answer - 4 `{:(,2SO_(2)(g),+,O_(2)(g),hArr,2SO_(3)(g)),("at Eq",x,,y,,z),("on reducing vol",2x,,2y,,2z),("new Eq.",2x-2a,,2y-a,,2z-2a),("total pressure",=2(x+y+z)-a,=2P_(1)-a,,,lt2P_(1)):}` |
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