1.

For the following reaction, the moles ofrequired to produce 990 gm H_2O are __________. 2C_(57)H_(110)O_(6) + 163O_(2)(g) to 114CO_(2)(g) + 110 H_(2)O(l)

Answer»


Solution :`2C_(57)H_(110)O_(6)(s)+1630_(2)(G)rarr114CO_(2)(g)+110H_(2)O(l)`
MOLE of` C_(57)H_(110)O_(6)=(2)/(110)xx "moles of "H_(2)O`


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