1.

For the formation of 3.65 g of hydrogen chloride gas, what volumes of hydrogen and chlorine gas are required at N.T.P conditions ?

Answer»

1.12 L, 1.12 L
1.12 L, 2.24 L
3.65 L, 1.83 L
1 L, 1 L.

Solution :`underset(22.4 L at NTP)(H_2(g) ) + underset(22.4 at NTP)(Cl_2(g) ) to underset(2 XX 36.5 g)(2HCL(g) )`
To obtained `2 xx 36.5 g ` of HCL `H_2` REQUIRED at NTP = 22.4 L
To obtained 3.65 g of HCl `H_2` required at NTP
` = (22.4 xx 3.65)/(2 xx 36.5) = 1.12 L`
`Cl_2 ` required= 1.12L (same)


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