1.

For the formation of 3.65 g of hydrogen chloride gas, what volumes of hydrogen gas and chlorine gas are required at N.T.P. conditions?

Answer»

1.12 lit, 1.12 lit
1.12 lit, 2.24 lit
3.65 lit, 1.83 lit.
1 lit., 1 lit.

Solution :`{:(H_(2)(G),+,Cl_(2)(g),rarr,2HCl(g)),("1 MOLE",,"1 mole",,"1 mole"),("22.4 L",,"22.4 L",,2xx36.5g):}`
`therefore" For FORMATION of 3.65 g HCl, "H_(2) or Cl_(2)" required"`
`=(22.4)/(2xx36.5)xx3.65L=1.12L`


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