1.

For the four successive transition elements (Cr, Mn, Fe and Co) ,the stability of +2 oxidation state will be there in which of the following order ?

Answer»

`Cr gt Mn gt Co gt Fe`
`Mn gtFe gt Cr gt Co`
`Fe gt Mn gt Co gt Cr`
`Co gt Mn gt Fegt Cr`

Solution :`Mn^(2+)(d^(5))` GETS highest stabilization due to HALF filled CONFIGURATION .In case of`Fe^(2+)(d^(6))` , additionof ONE extra electron in the subshelldestabilizes it. Addition of two electronsincase of `Co^(2+)(d^(7))` destabilizes itmore . `Cr^(2+)(d^(4))` has one vacant subshell. `Fe^(2+)` gets more stabilizationas comparedto `Cr^(2+)` through exchange energy . So, the correct order is`Mn gt Fe gt Cr gtCo`.


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