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For the galvanic cellAg | AgCl (s), KCl(0.2 M)||KBr(0.001 M), AgBr(s)|Ag,calculate the emf generated and assign correct polarity to each electrode for a spontaneous process after taking into account the cell reaction at 25^@C.K_(sp)(AgCl) = 1.8 xx 10^(-10), K_(sp)(AgBr) = 3.3 xx10^(-13) |
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Answer» SOLUTION :Calculate `[AG^+]` from `K_(sp)`values for both the HALF cells and then calculate `E_("cell") ` for `Ag|Ag^(+) (c_1) | Ag^(+) (c_2) | Ag ` 0.037V |
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