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For the gaseous reaction, H_(2)+Cl_(2) to 2HCl. If 40 ml of hydrogen completely reacts with chlorine then find out the the required volume of chlorine and volume of produced of HCl? |
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Answer» Solution :According to GAY Lussac's Law: `H_(2)+Cl_(2) to 2HCl` `therefore` 1 ML of `H_(2)` will react will 1 ml of `Cl_(2)` and 2 ml of HCl will produce. `therefore` 40 ml of `H_(2)` will react with 40 ml of `Cl_(2)` and 80 ml of HCl will produce REQUIRED vol. of `Cl_(2)=40` ml , produced vol. of HCl=80 ml |
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