1.

For the gaseous reaction, N_(2)O_(4) rarr 2NO_(2)

Answer»

`DELTAH lt DeltaE`
`DeltaH = DeltaE`
`DeltaH = 0`
`DeltaH gt DeltaE`

Solution :`N_(2)O_(4)(g)rarr2NO_(2)(g)`
For this reaction `Deltan_(g)=2-1=1`
`Deltan_(g)` is positive is i.e., there is an INCREASE in the number of gaseous moles then `DeltaH gt DeltaE`.


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