1.

For the given cel, Mg|Mg^(2+)||Cu^(2+)|Cu _____

Answer»

Mg is cathode
CU is cathode
The cell reaction is `Mg+Cu^(2+) to Mg^(2+)+Cu`
Cu is the oxidising agent

Solution :Left side of the cell represent oxidation half-cell and RIGHT side represent reduction half-cell. In galvanic cell, anode of Mg|`Mg^(2+)` is on left side, where oxidation reaction occur.
Oxidation : `Mg_((S)) to Mg^(2+)+2E^(-)`. .(i)
So, Option (A) is not right.
In this cell, cathode of `Cu^(2+)|Cu` is on right side, where reduction reaction occur.
Reduction : `Cu^(2+)+2e^(-) to Cu` . . .(ii)
Total reaction in cell (iii)=(i)+(ii)
(iii) Redox reaction :

So, option (C) is right.
* In this reaction oxidation of Mg and reduction of `Cu^(2+)` occur. So `Cu^(2+)` is oxidizing and Cu is not Oxidizing. So option (D) is wrong.


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