For the given reaction at constant pressure, `{:(,nA(g)hArr,A_n(g)),("Initial moles",1,0),("Final moles",1-alpha,alpha/n):}` Then the correct relation between initial density `(d_i)` and final density `(d_f)` of the system is :A. `[(n-1)/(n)][(d_(f)-d_(i))/(d_(f))]=alpha`B. `(n)/(n-1)([d_(f)-d_(i)])/(d_(f))=alpha`C. `[(n-1)/(n)][(d_(i)-d_(f))/(d_(i))]=alpha`D. `(1)/((n-1))[(d_(i)-d_(f))/(d_(i))]=alpha`

For the given reaction at constant pressure, `{:(,nA(g)hArr,A_n(g)),("

1.	For the given reaction at constant pressure, `{:(,nA(g)hArr,A_n(g)),("Initial moles",1,0),("Final moles",1-alpha,alpha/n):}` Then the correct relation between initial density `(d_i)` and final density `(d_f)` of the system is :A. `[(n-1)/(n)][(d_(f)-d_(i))/(d_(f))]=alpha`B. `(n)/(n-1)([d_(f)-d_(i)])/(d_(f))=alpha`C. `[(n-1)/(n)][(d_(i)-d_(f))/(d_(i))]=alpha`D. `(1)/((n-1))[(d_(i)-d_(f))/(d_(i))]=alpha`
Answer» Correct Answer - B Total moles at equilibrium `=1-alpha+alpha//n=1+[(1)/(n)-1]alpha` So using `(d_(i))/(d_(f))=1+[(1)/(n)-1]alpha`

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