InterviewSolution
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InterviewSolution
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For the hypothetical reactions, the equilibrium constant `(K)` value are given `AhArrB,K_(1)=2,BhArrC,K_(2)=4,` `ChArrD,K_(3)=3` The equilibrium constant (K) for the reaction `AhArrD` isA. `48`B. `6`C. `27`D. `24` |
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Answer» Correct Answer - D The reaction `AhArrD` is obtained by adding the three given reactions `:. K=K_(1)xxK_(2)xxK_(3)=2xx4xx3=24` or `K_(1)=([B])/([A]), K_(2)([C])/([B]), K_(3)=([D])/([C])` On multiplying `K_(1),K_(2)` and `K_(3)`, we get `K=K_(1)xxK_(2)xxK_(3)=([D])/([A])=24` |
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