1.

For the neutralisation of `1` mol of `H_(2)SO_(4)` with `2` mols of `NaOH` in dilute solutions the heat evolved isA. `=57.0 kJ`B. ` lt 57.0 kJ`C. ` gt 57.0 kJ`D. Unpredictable

Answer» Correct Answer - C
`1 "mol"H_(2)SO_(4)=2"mol"H^(+)`
`2"mol"NaOH=2"mol"OH^(-)`
`2H^(+)(aq)+2OH^(-)(aq)to2H_(2)O(l)`
`DeltaH=57kJmol^(-1)xx2"mol"`
`=114kJ gt 57kJ`


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