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For the neutralisation of `1` mol of `H_(2)SO_(4)` with `2` mols of `NaOH` in dilute solutions the heat evolved isA. `=57.0 kJ`B. ` lt 57.0 kJ`C. ` gt 57.0 kJ`D. Unpredictable |
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Answer» Correct Answer - C `1 "mol"H_(2)SO_(4)=2"mol"H^(+)` `2"mol"NaOH=2"mol"OH^(-)` `2H^(+)(aq)+2OH^(-)(aq)to2H_(2)O(l)` `DeltaH=57kJmol^(-1)xx2"mol"` `=114kJ gt 57kJ` |
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