1.

For the non -stoichiometric reaction : 2A+B rarr C+D the following data were obtained in three separate experiments experiments all at 298 K The rate law for the formation of C is

Answer»

`(dC)/(DT) = k[A][B]`
`(dC)/(dt)=k[A]^(2)[B]`
`(dC)/(dt)=k[A][B]^(2)`
`(dC)/(dt)=k[A]`

SOLUTION :(D) Initial rate `(dC)/(dt) = k [A]^(x) [B]^(y) `
`1.2xx10^(-3) = k(0.1)^(x) (0.1)^(y)`
`1.2xx10^(-3)=k(0.1)^(x) (0.2)^(y)`
`2.4xx10^(3)= k(0.2)^(x)(0.1)^(y)`
DIVIDING EQ (ii) by (i)
`(1.2xx10^(-3))/(1.2xx10^(-3)) = ((2)/(1)^(y))`
or `1=2^(y) :. y=0`
Dividing eq (III ) by (i)
`(2.4xx10^(-3))/(1.2xx10^(-3))=2^(x)`
`2=2^(x):. y=1 `
`:. ` Rate = k [A]


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