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For the principal values, evaluate each of the following:`tan^(-1){2cos(2s in^(-1)1/2)}``"cot"[sin^(-1){cos(tan^(-1)1)}]` |
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Answer» `tan^(-1)[2 cos ( 2 sin^(-1)""(1)/(2))]` `=tan^(-1)[2 cos(2 sin^(-1)sin""(pi)/(6))]` `=tan^(-1)[2 cos (2*(pi)/(6))]` `=tan^(-1)(2*(1)/(2))=tan^(-1)(1)` `=tan^(-1)(tan""(pi)/(4))=(pi)/(4)` |
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