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For the production of equalamounts of hydrogen fromthe following reactions, which metal, An or Al,is less expensive if Zn costsabouthalf as much as Al an a mass basisand by how much ? {:(An + 2HCl to ZnCl_(2)+H_(2) ),(2Al+6HCl to2AlCl_(3)+3H_(2)):} |
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Answer» Solution :1 mole of `H_(2)` is produced by 1 mole, i.e., 65 g of Zn and 1 mole of `H_(2)`is produced by `(2)/(3)` mole, i.e., `(2 xx 27)/( 3)` g of AL = 18 g of Al Now that Zn costs about half as MUCHAS Al, to purchase Zn and Al to PRODUCE the same AMOUNT of `H_(2)` the costratio of Znand Al will be 65:36 Al is thus lessexpensive by `(65-36)/( 65) xx 100` ,i.e.,`44.61 %` |
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