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For the raction `B_(2)H_(6)(g)+3O_(2)(g)rarrB_(2)O_(2)(s)+3H_(2)O(l)` `DeltaE=-2143.2KJ` Calculate `DeltaH` for the reaction at `25^(@)C`A. `-2148.2KJmol^(-1)`B. `-2138.6KJmol^(-1)`C. `-2133.2KJmol^(-1)`D. `-2143.2KJmol^(-1)`

Answer» Correct Answer - C
For `B_(2)H_(6)(g)+3O_(2)(g)rarrB_(2)O_(3)(s)+3H_(2)O(l)`
`DeltaE=-2143.2KJ`
`Deltan=0-2=-2`
Now from `DeltaH=DeltaE+DeltanRT`
`-2143.2+(-2)xx8.314xx10^(-3)xx298`
`=-2148.2KJ mol^(-1)`


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