1.

For the reaction 2A+B +C rarr A_(2)B+C the rate law has been found to be Rate = k[A] [B]^(2)withk = 2.0xx10^(-6) mol^(-2) L^(2)s^(-1) . The initial rate of reaction with [A] =0.1 mol L^(-1) [B] = 0.2 mol L^(-1) and [C] = 0.8 mol L^(-1) s^(-1)

Answer»

`6.4xx10^(-8) "MOL L"^(-1)s^(-1)`
`4xx10^(-3) "mol L"^(-1)s^(-1)`
`8.0xx10^(-9) "mol L"^(-1) s^(-1)`
`4.0 xx10^(-7) "mol L"^(-1)s^(-1)`

Solution :(C ) Rate `= k[A] [B]^(2)`
`= (2.0xx10^(-6))(0.1) (0.2)^(2)`
`=8xx10^(-9)`


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